MAD101_-_SP_2024_-_Block_5_-_FE_1940.webp
night_owl1

MAD101_-_SP_2024_-_Block_5_-_FE_1940.webp

(Choose 1 answer)
What is the output of the algorithm?
Procedure product(n: integer)p:=0;for i:=1 to (3*n) do for j:=1 to (2*n) do for k:=1 to (4*n) do p:=i*j*k;
Print(p)
A. 24n^3
B. 1024n^3
C. (3n)!(2n)!(4n)!
D. 2n^3
E. 4n^3
FUO
: 19

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