Multiple choices 28/50
Answer (Choose 1 answer)
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What is the output of the algorithm ?
Procedure product(n: integer)p:=0;for i:=1 to (3*n) do for j:=1 to (2*n) do for k:=1 to (4*n) do p:=i*j*k;
Print(p)
A. 24n^3
B. 1024n^3
C. (3n)!(2n)!(4n)!
D. 2n^3
E. 4n^3
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