MAS291_-_FA_2023_-_B3W_-_FE_1295.webp
minhha92

MAS291_-_FA_2023_-_B3W_-_FE_1295.webp

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Α. 63.8402\le\mu\le65.0798
Β. 63.9399\le u\le64.9801
C. 67.841\le u\le85.0823
D. 53.841\le u\le75.0823
Assume that impact energy is normally distributed with \sigma=1 We want to find a 95% CI for µ, the mean impact energy. By a sample, we get n=10 and sample mean = 64.46. The resulting 95% CI is found by:Let Z0.025 1.96; 20.05-1.645 and note that all calculation need to be rounded to 4 decimal places.

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