Question: 22
(Choose 1 answer)
(See picture)
A. (i)
B. (ii)
C. (iii)
D. (iv)
E. (v)
Consider the vector-valued function f: R3 → R³:
f(x, y, z) =
x²
V +2y²+z2
e-x²-2y2-3z²
In(1+x²+3y²+2z²)]
The (3,2)-entry of the Jacobian of f at (x, y, z) = (1,1,0) is:
(i) 1.2
འཝ
(iii) 0.4
(ii) 0
(iv) 1/√3
(v) 2/√3
