Kizspy | Question: 37
(Choose 1 answer)
A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Assume that bowler's scores are normally distributed. Find the 95% confidence interval of the mean score of all bowlers.
Α. (188.5, 195.6)
Β. (189.5, 194.5)
C. (186.5, 197.5)
D. (187.3, 196.1)
E. None of the other choices is correct
Let
Zo.05 1.65, Z0.025 = 1.96,to.05,39 1.68, to.025,39 = 2.02.
