Answer (Choose 1 answer)
What will happen when you attempt to compile and run the following code?
class Base{
Base(){
System.out.println("Base");
}
}
public class Checket extends Base{
public static void main(String argv[]){
Checket c = new Checket();
super();}
Checket(){
System.out.println("Checket");}
}
A. Compile time error
B. Checket followed by Base
C. Base followed by Checket
D. runtime error
Iv
1
